Problem 3.12
A mole of an ideal monatomic gas undergoes a reversible adiabatic expansion from $V_i$ to $V_f = 2V_i$. The initial temperature is $T_i = 300\ \textK$. Find the final temperature, work done, and change in internal energy.Known: $n=1$, $\gamma = \frac53$, $V_f/V_i = 2$, $T_i = 300\ \textK$, adiabatic ($Q=0$), reversible.
Concept: For reversible adiabatic process, $TV^\gamma-1 = \textconstant$. Problem 3
Solution:
Answer: $T_f = 189\ \textK$, $W = -1.39\ \textkJ$, $\Delta U = -1.39\ \textkJ$. Answer: $T_f = 189\ \textK$, $W = -1
Check: Adiabatic expansion → cooling → $T_f < T_i$ ✔.
Additional notes: Include a “Common Mistake” box (e.g., “Do not use $PV^\gamma = \textconst$ without checking reversibility”). Additional notes: Include a “Common Mistake” box (e
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