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Rectangular field with 600m fencing, one side against river (no fence). Max area.
Let (x) = side parallel to river, (y) = other side. (x + 2y = 600) → (A = xy = y(600-2y)) → derivative → (y=150), (x=300).
While specific editions vary slightly, a standard copy of Differential and Integral Calculus by Feliciano and Uy contains the following vital sections in Chapter 4:
Find two numbers whose sum is 20 and product is maximum.
Solution: (x + y = 20), (P = xy = x(20-x) = 20x - x^2)
(P' = 20 - 2x = 0) → (x=10, y=10), max (P=100)
Check out the following product comparison and decide yourself about the best offer (competition prices date 02.2020, 1-year licenses).
| iREPAIR (OUR SOFTWARE) | dr.fone - System Repair (iOS) | Tenorshare ReiBoot | |
|---|---|---|---|
| NUM OF DEVICES | 1-6 | 1-5 | 1-5 |
| SUBSCRIPTION AUTO-RENWAL | NO | YES | YES |
| HIDDEN FEES | NO | ? | ? |
| ABILITY TO MOUNT DEVICE DATA | YES | NO | NO |
| BACKUP | YES | NO | NO |
| ORIGIN | EUROPEAN UNION |
CHINA |
CHINA |
| PRICE | $39 USD |
$79.83 USD | $49,14 USD |
| PRICE FOR ULTIMATE LICENSE | $199 USD |
$399 USD | $399 USD |
| TRY NOW THE BEST SOLUTION |
Rectangular field with 600m fencing, one side against river (no fence). Max area.
Let (x) = side parallel to river, (y) = other side. (x + 2y = 600) → (A = xy = y(600-2y)) → derivative → (y=150), (x=300).
While specific editions vary slightly, a standard copy of Differential and Integral Calculus by Feliciano and Uy contains the following vital sections in Chapter 4:
Find two numbers whose sum is 20 and product is maximum.
Solution: (x + y = 20), (P = xy = x(20-x) = 20x - x^2)
(P' = 20 - 2x = 0) → (x=10, y=10), max (P=100)
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